Equation of parabola which is symmetric about y-axis with vertex (0, 0) and pass through (6, 3).

Equation of parabola which is symmetric about y-axis with vertex (0, 0) and pass through (6, 3). Correct Answer x2=12y

Equation of parabola which is symmetric about y-axis with vertex (0, 0) is x2=4ay Since parabola pass through (6, 3) then 62=4a*3 => a=3. So, equation is x2=12y.

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If focus of parabola is F (2, 5) and equation of directrix is x + y=2, then find the equation of parabola.