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The orbital velocity of a satellite orbiting the earth is half the escape velocity of the earth. What is the height above the surface of the earth at which it is orbiting? (Let the radius of the earth (R) = 6400 km).

The orbital velocity of a satellite orbiting the earth is half the escape velocity of the earth. What is the height above the surface of the earth at which it is orbiting? (Let the radius of the earth (R) = 6400 km). Correct Answer 6400 km

Orbital velocity (v) = 1/2 Escape velocity (v’) = 1/2 We know; v = v’/2 v2 = v’2/4 = /4 1 / (R+h) = 1 / (2R) 2R = R + h h = R Therefore; h = 6400km.

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