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An object is projected vertically upwards with a velocity (gr) 1/2. What is the maximum height reached by the object if “R” is the radius of the earth and “g” is the acceleration due to gravity?

An object is projected vertically upwards with a velocity (gr) 1/2. What is the maximum height reached by the object if “R” is the radius of the earth and “g” is the acceleration due to gravity? Correct Answer R

From the law of conservation of energy, we have; (m x v2)/2 – (G x M x m)/R = -(G x M x m)/(R+h) m = Mass of object M = Mass of earth h = Maximum height of the object v = Velocity of projection (m x v2)/2 – (g x m x R) = -(g x m x R2)/(R+h) (g x R)/2 = (g x R x h)/(R+h) Therefore; h = R.

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