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A 200 bus power system has 160 PQ bus. For achieving a load flow solution by N-R in polar coordinates, the minimum number of simultaneous equation to be solved is ___________

A 200 bus power system has 160 PQ bus. For achieving a load flow solution by N-R in polar coordinates, the minimum number of simultaneous equation to be solved is ___________ Correct Answer 359

Total buses = 200 PQ buses = 160 PV buses = 200-160 = 40 Slack bus = 1 Total number of equation = (40-1)*1 + (160*2) = 359.

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