0.001 M NaOH দ্রবণের pH হবে-
A
3
B
4
C
10
D
11
Correct Answer: 11
NaOH ↔️ Na+ + OH- [OH-] = [NaOH] = 0.001M POH = -log[OH-] = -log(0.001) = 3pH = 14 - POH = 14 - 3 = 11