0.005M H₂SO₄ দ্রবণের pH কত ?
A
2
B
5
C
0.5
Correct Answer: 2
H2SO4 ↔️ 2H+ + SO42-[H+] =2[H2SO4] = 2 × 0.005 = 0.01MpH = -log[H+] = -log(0.01) = 2