0.02M NaOH দ্রবণের pH কোনটি?

A 1.69
B 8.77
C 12.30
D 13.31

Correct Answer: 12.30

NaOH ↔️ Na+ + OH-[OH-] = [NaOH] = 0.02MPOH = -log[OH-] = -log(0.02) = 1.6989pH = 14 - POH = 14 - 1.698 = 12.30 
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