0.02M NaOH দ্রবণের pH কোনটি?
A
1.69
B
8.77
C
12.30
D
13.31
Correct Answer: 12.30
NaOH ↔️ Na+ + OH-[OH-] = [NaOH] = 0.02MPOH = -log[OH-] = -log(0.02) = 1.6989pH = 14 - POH = 14 - 1.698 = 12.30