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What happens if the following program is compiled and executed? interface MyInterface{ void display(); } interface MySubInterface extends MyInterface{ void display(); } public class Test implements MySubInterface{ public void display(){ System.out.print("Welcome to Examveda."); } public static void main(String args[]){ Test t = new Test(); t.display(); } }

What happens if the following program is compiled and executed? interface MyInterface{ void display(); } interface MySubInterface extends MyInterface{ void display(); } public class Test implements MySubInterface{ public void display(){ System.out.print("Welcome to Examveda."); } public static void main(String args[]){ Test t = new Test(); t.display(); } } Correct Answer The code will compile and execute successfully showing the output Welcome to Examveda.

Answer: Option 3

The program will compile and execute successfully as you can declare methods with same name in an interface and the method of either interface can be used, implying the option a is incorrect. The option B and D are incorrect as the methods of an interface are implicitly public and abstract.

Related Questions

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How many objects will be created? String a = new String("Examveda"); String b = new String("Examveda"); String c = "Examveda"; String d = "Examveda";
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