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An electron and a proton starting from rest get accelerated through potential difference of 100 kV. The final speeds of the electron and the proton are Ve and Vp respectively. Which one of the following relations is correct?

An electron and a proton starting from rest get accelerated through potential difference of 100 kV. The final speeds of the electron and the proton are Ve and Vp respectively. Which one of the following relations is correct? Correct Answer V<sub>e</sub> &gt; V<sub>p</sub>

  • The work done by the electrostatic force on an electron or proton is the product of the charge and the potential difference traveled through.
  • According to the work-energy theorem, the kinetic energy gained by the particle is equal to the work done on it.

          Change in KE= charge x potential difference

         ΔKE=We= Q.V

         1/2 Mv2= Q.V

  • From the above equation, it is clear that the velocity of a particle is inversely proportional to the mass of a particle, therefore the particle having less mass vill posses more velocity.
  • Hence, electron having less mass than the proton will have a greater velocity than the proton i. e Ve > Vp

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