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Reaction of LiAlH4 with one equivalent of Me3N∙HCl gives a tetrahedral compound, which reacts with another equivalent of Me3N∙HCl to give compound N. The compound N and its geometry, respectively, are: 

Reaction of LiAlH4 with one equivalent of Me3N∙HCl gives a tetrahedral compound, which reacts with another equivalent of Me3N∙HCl to give compound N. The compound N and its geometry, respectively, are:  Correct Answer AlH<sub>3</sub>(NMe<sub>3</sub>)<sub>2</sub> and trigonal bipyramidal

Concept:

  • The reaction can be explained on the basis of adduct formation between a Lewis base and a Lewis Acid. Let us take an example:

BF3 -

  • This molecule does not have its octet fulfilled.
  • To fill its octet, it can accept a lone pair and act as a Lewis acid.

NH3 -

  • Nitrogen has an extra lone pair on its head.
  • To get rid of it it can donate this pair acting as a Lewis base.

The interaction - 

  • Lewis acid has a vacant unoccupied orbital called LUMO.
  • Lewis bases have fulfilled occupied orbital called HOMO.
  • Electron density from HOMO is donated to LUMO of Lewis acid.
  • A simple HOMO and LUMO interaction is shown below:

Additional Information

  • The bulkier NMe3 groups are kept in the equatorial plane and to avoid repulsion according to Bent's Rule. 

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