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What does the circuit in the figure given below represent?

What does the circuit in the figure given below represent? Correct Answer Band Stop Filter

At low frequency: 

The Inductor acts as a short circuit

The capacitor acts as an open circuit.

Vout ≠ 0

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At high frequency:

The Inductor L acts as an open ci

The capacitor acts as a short circuit

Vout ≠ 0

[ alt="F1 T.S 29.8.20 Pallavi D4" src="//storage.googleapis.com/tb-img/production/20/09/F1_T.S_29.8.20_Pallavi_D4.png" style="width: 249px; height: 180px;">

It is clearly observed that output voltage is non zero at low frequency and high frequency.

Observation:

Option 1: This circuit can't be a Bandpass filter because a bandpass filter output voltage is zero for low frequency and high-frequency.

Option 2: This circuit can be a bandstop filter because the bandstop filter output voltage is non zero for low frequency and high-frequency and it is zero at some particular medium frequency.

Option 3: This circuit can't be a differential amplifier because the differential amplifier output voltage is proportional to the difference of applied input voltages.

Option 4: This circuit can't be a differentiator because the differentiator is a Highpass filter and its output voltage is non zero for high frequency and it is zero for the low frequencies.

Hence, the given circuit is the Bandstop Filter.

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