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A pack of the card contains some Black cards, Red cards and Blue cards such that the probability of picking a Black card is 2/7 and the probability of picking a Red card is 1/2. If all the cards are numbered starting from 1, 2, 3, …. and so on, then what is the probability of getting one card numbered as multiple of 3 or 7 out of the total cards.

A pack of the card contains some Black cards, Red cards and Blue cards such that the probability of picking a Black card is 2/7 and the probability of picking a Red card is 1/2. If all the cards are numbered starting from 1, 2, 3, …. and so on, then what is the probability of getting one card numbered as multiple of 3 or 7 out of the total cards. Correct Answer 3/7

GIVEN :

Probability of picking a Black card is 2/7 and the probability of picking a Red card is 1/2.

 

ASSUMPTION :

Let the total number of cards = LCM of 7 and 2 = 14

 

CALCULATION :

Number of black cards = 4,

Number of red cards = 7

Number of blue cards = 14 - 4 - 7 = 3

Total cards multiple of 3 or 7 = {3, 6, 7, 9, 12, 14} = 6

∴ Required probability = 6/14 = 3/7

 

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