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What is the equation of the straight line parallel to 2x - 3y = 1 and passes through the point (-3,2)

What is the equation of the straight line parallel to 2x - 3y = 1 and passes through the point (-3,2) Correct Answer 2x - 3y + 12 = 0

Concept:

Equation of a Line Parallel to a Line:

Let, ax + by + c = 0 (b ≠ 0) be the equation of the given straight line. So, the equation of a line parallel to a given line is ax + by + k = 0

​Where k is constant.

The slopes of parallel lines are equal.

 

Calculation:

Hare, equation of the straight line parallel to 2x - 3y = 1

Let, equation of required line be 2x - 3y + k = 0

Now, this line passing through (-3, 2)

∴2(-3) - 3(2) + k = 0

⇒ -6  - 6 + k = 0 

⇒ k = 12

∴ Equation of required line 2x - 3y + 12 = 0

Hence, option (2) is correct. 

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