If each address space represents one byte of storage space, how many address lines are needed to access RAM chips arranged in a 4 × 6  array, where each chip is 8K × 4 bits?

If each address space represents one byte of storage space, how many address lines are needed to access RAM chips arranged in a 4 × 6  array, where each chip is 8K × 4 bits? Correct Answer 17

The correct answer is "option 4".

CALCULATION:

Address type - Byte Addressable

Total no. of RAM Chips = 6 x 4 = 24 chips

Number of bits needed  = ⌈ log224 ⌉ = 5 bits

Size of RAM chips  8K × 4 =  23 x 210 x 2=215 bits

Number of bits needed  = ⌈ log2215⌉ = 15 bits

Total number of bits = 12 + 5 bits = 17 bits      

Related Questions

A teacher asked the class to subtract 5 from 75.70% of the class said: 25. Their work was shown as: \(\begin{array}{*{20}{c}} {\begin{array}{*{20}{c}} 7&5 \end{array}}\\ {\underline {\begin{array}{*{20}{c}}\ { - 5} \ \ \ &{} \end{array}} }\\ {\underline {\begin{array}{*{20}{c}} 2&5 \end{array}} } \end{array}\) Which of the following describes the most appropriate remedial action that the teacher should take to clarify this misconception?