A small object carrying a charge -5 × 10-9 Coulomb experiences a downward force of 20 × 10-9 Newton when placed at a certain point in an electric field. The electric field intensity at the point is
A small object carrying a charge -5 × 10-9 Coulomb experiences a downward force of 20 × 10-9 Newton when placed at a certain point in an electric field. The electric field intensity at the point is Correct Answer 4 Newton/Coulomb upward
CONCEPT:
- Electric field force: When a charge moves in an electric field, a force will act on it, that is known as electric field force.
- Due to the electric field, Force is always in the direction of the electric field if the charge is positive.
F = qE
where F is the force due to the electric field, q is the charge, and E is the electric field.
CALCULATION:
Given that q = -5 × 10-9 Coulomb and F = 20 × 10-9 Newton
F = qE
20 × 10-9 = -5 × 10-9 × E
E = 4 Newton/Coulomb
- Since the charge is negative so the direction of the electric field will be opposite to the direction of Force (downward).
E = 4 Newton/Coulomb upward.
So the correct answer will be option 3.
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Feb 20, 2025