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A communication receiver has an intermediate frequency of 9 MHz. What is the frequency of its oscillator when it is tuned to 15 MHz?

A communication receiver has an intermediate frequency of 9 MHz. What is the frequency of its oscillator when it is tuned to 15 MHz? Correct Answer 24 MHz

Concept:

For super heterodyne receiver:

fi = fl - fs

Where,

fl = Local oscillator frequency

fi = Intermediate frequency

fs = Desired signal frequency

Calculation:

Given,

fi = 9 MHz

fs = 15 MHz

fi = fl - fs

fl = fi + fs

= (9 + 15) MHz

= 24 MHz

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