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Louis Pasteur mixes two acids HCL and HNO3 in the ratio 7 ∶ 5 and filled it in a container. When 9 liters of solution is taken out and the can is filled with HNO3, the ratio of HCL and HNO3 becomes 7 ∶ 9. How many liters of HCL was contained by the container initially?

Louis Pasteur mixes two acids HCL and HNO3 in the ratio 7 ∶ 5 and filled it in a container. When 9 liters of solution is taken out and the can is filled with HNO3, the ratio of HCL and HNO3 becomes 7 ∶ 9. How many liters of HCL was contained by the container initially? Correct Answer 21 L

Given∶

Initial ratio = 7 ∶ 5

9 liters of solution is taken out and the can is filled with HNO3 

New ratio = 7 ∶ 9

Formula Used∶

 

Basics of Ratios and Linear equations.

Calculation∶

Let the containers initially contains 7x and 5x of HCL and 

HNO3 respectively,

Quantity of HCL in solution left = L = L

Quantity of HNO3 in solution left = L = L

Resulting ratio,

⇒ / + 9 = 7/9

⇒ (28x - 21) / (20x + 21) = 7/9

⇒ 252 x - 189 = 140x + 147

⇒ 112x = 336

⇒ x = 336/112 = 3

Thus, Quantity of HCL = 7x = 7 × 3 = 21

∴ The containers contained 21 liters of HCL.

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