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If there are three numbers which are co-prime to each other such that the product of first two numbers is 1102 and that of last two is 2146. Calculate the sum of three numbers?

If there are three numbers which are co-prime to each other such that the product of first two numbers is 1102 and that of last two is 2146. Calculate the sum of three numbers? Correct Answer 114

∵ 3 numbers are co-prime to each other; they contain 1 as common factor

Also, given two products have the middle number is common.

Middle number = HCF of 1102 and 2146 = 58

First number = 1102/58 = 19

Third number = 2146/58 = 37

∴ required sum = (37 + 19 + 58) = 114

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