A pyramid having square base of side 16 cm is cut horizontally at some height. The frustum thus formed has the volume equal to 834 cm3. If the side of square base of upper surface of the frustum is 7 cm, the height at which the cut was made is 6 cm from the base, then find the total height of the original pyramid.
A pyramid having square base of side 16 cm is cut horizontally at some height. The frustum thus formed has the volume equal to 834 cm3. If the side of square base of upper surface of the frustum is 7 cm, the height at which the cut was made is 6 cm from the base, then find the total height of the original pyramid. Correct Answer 32/3 cm
When pyramid is cut at height 6 cm, one part will be frustum of height 6 cm and other part is a pyramid only.
The smaller pyramid will have the square base of side 7 cm (As the side of square base of upper surface of the frustum is 7 cm)
Suppose the height of smaller pyramid = h cm
∴ Total height of the original pyramid = (6 + h) cm
∴ Volume of original pyramid = Volume of smaller pyramid + Volume of frustum
⇒ 1/3 × (16)2 × (6 + h) = 1/3 × (7)2 × h + 1/3 × 6 ×
⇒ 256/3 × (6 + h) = 49/3 × h + 2 ×
⇒ 1536 + 256h = 49h + 2502
⇒ 207h = 966
⇒ h = 14/3 cm
∴ Total height of the original pyramid = 6 + 14/3 = 32/3 cm