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There is a pyramid on a base which is a regular hexagon of side a cm. If every slant edge of this pyramid is of length 2a, then the volume of the pyramid is?

There is a pyramid on a base which is a regular hexagon of side a cm. If every slant edge of this pyramid is of length 2a, then the volume of the pyramid is? Correct Answer 3a<sup>3</sup>/2 cm<sup>3</sup>

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⇒ Area of base = 6 × (√3/4) × a2 = 3√3a2/2 cm2

⇒ Height of the pyramid = √(slant edge2 – side2) = √(4a2 – a2) = √3a

⇒ Volume of pyramid = (1/3) × Base area × Height = (1/3) × (3√3a2/2) × √3a = 3a3/2 cm3 

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