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Find the approximate value which should replace the question mark (?) in the following question. 4.99% of 40.0099% of 1999 – 23.87% of 350 = ? + √575

Find the approximate value which should replace the question mark (?) in the following question. 4.99% of 40.0099% of 1999 – 23.87% of 350 = ? + √575 Correct Answer -68

Follow BODMAS rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is,

4.99% of 40.0099% of 1999 – 23.87% of 350 = ? + √575

Taking the approximate values as,

4.99 ≈ 5, 40.0099 ≈ 40, √575 ≈ √576, 23.87 ≈ 24

⇒ 5% of 40% of 2000  – 24% of 350  = ? + √576

⇒ 0.05 × 0.4 × 2000 - 84 = ? + 24

⇒ 40 - 84 - 24 = ?

∴ ? = -68

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