Which of the following is valid for Boolean algebra but NOT for ordinary algebra?

Which of the following is valid for Boolean algebra but NOT for ordinary algebra? Correct Answer X + (Y.Z) = (X + Y).(X + Z)

In Boolean algebra:

X + (Y.Z) = (X + Y).(X + Z)

But not true in ordinary algebra:

Example: X = 1, Y = 2 and Z = 3

LHS = X + (Y.Z) = 1 + 2 × 3 = 7

RHS = (1 + 2).(1 + 3) = 3 × 4 = 2

Important Point:

Law

Remark

A + B = B + A

Commutative Law

A + (B + C) = (A + B) + C

Associative Law

A (B + C) = AB + AC

Distributive Law

A + 1 = 1

Identity Law/Redundancy Law

A + 0 = A

A + A = A

A + A̅ = 1

A + AB = A

Absorption Law

A̅ = A

Involution Law

A + A̅B = A + B

-

B̅ + B̅ = B

 

 

Confusion Points 

Here Ordinary algebra means simple maths algebra. 
Option 2) will include only in boolean algebra. But option 3) is true for both Boolean as well as Maths algebra.

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