In a class, the number of girls is 33(1/3)% and rest are boys. The average marks of boys in English are 10% less than that of girls and the overall average marks are 84. If average marks of girls in English are G and average marks of boys in English are B, which of the following is/are correct? The Total number of students is 105. I. B + G = 171 II. B – G = 9 III. B × G = (G/10)2 × G IV. B : G = 10 : 9
In a class, the number of girls is 33(1/3)% and rest are boys. The average marks of boys in English are 10% less than that of girls and the overall average marks are 84. If average marks of girls in English are G and average marks of boys in English are B, which of the following is/are correct? The Total number of students is 105. I. B + G = 171 II. B – G = 9 III. B × G = (G/10)2 × G IV. B : G = 10 : 9 Correct Answer I and III
Given:
Total number of students = 105
Number of girls = 33(1/3)% of 105
Number of boys = 105 – Number of girls
B = 90% of G
Overall average marks in English = 84
Formula Used:
Average = Sum of values/Number of values
Calculation:
Number of girls = 33(1/3) × 105/100
⇒ 1/3 × 105
⇒ 35
Number of boys = 105 – 35
⇒ 70
B = 90% of G
⇒ B = 90/100 × G
⇒ B = (9/10)G
Sum of marks of boys in English/70 = B
⇒ Sum of marks of boys in English = 70B
Sum of marks of girls in English/35 = G
⇒ Sum of marks of girls in English = 35G
Sum of marks in English/105 = 84
⇒ Sum of marks in English = 8820
⇒ 70B + 35G = 8820
⇒ 70 × (9/10)G + 35G = 8820
⇒ 63G + 35G = 8820
⇒ 98G = 8820
⇒ G = 90
B = 9/10 × 90
⇒ B = 81
I. B + G = 171
81 + 90 = 171
⇒ I is correct
II. B – G = 9
81 – 90 = – 9
⇒ II is not correct
III. B × G = (G/10)2 × G
LHS = 81 × 90
⇒ 92 × 90
⇒ (90/10)2 × 90
⇒ (G/10)2 × G = RHS
⇒ III is correct
IV. B : G = 10 : 9
⇒ B : G = 81 : 90 = 9 : 10
⇒ IV is not correct
∴ I and III are correct