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Find the interval in which the function f(x) = x2 - 2x is strictly increasing ?

Find the interval in which the function f(x) = x2 - 2x is strictly increasing ? Correct Answer (1, ∞)

Concept:  

If f′(x) >  0 at each point in an interval, then the function is said to be strictly increasing.

Calculations:

Given , f(x) = x2 - 2x 

Differentiating, we get

f'(x) = 2x - 2

f(x) is strictly increasing function

∴ f'(x) > 0

⇒ 2x - 2 > 0

⇒ x > 1

∴ x ∈ (1, ∞)

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