If 2cos2θ - 1 = 0 and θ is acute, then what is the value of (cot2θ - tan2θ)?
If 2cos2θ - 1 = 0 and θ is acute, then what is the value of (cot2θ - tan2θ)? Correct Answer 0
2 cos2θ - 1 = 0
∴ cos2θ = ½
∴ cosθ = ±1/√2
θ is acute so θ = π/4
So, cot2θ - tan2θ = cot2π/4 - tan2π/4 = 1 - 1 = 0
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Feb 20, 2025