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A mixture comprising of 50% concrete, 30% cement and 20% sand was made. More cement was added in 60 kg of mixture in order to obtain a new mixture with 5/12 part of cement. The sand present in new mixture is what part of the new mixture?

A mixture comprising of 50% concrete, 30% cement and 20% sand was made. More cement was added in 60 kg of mixture in order to obtain a new mixture with 5/12 part of cement. The sand present in new mixture is what part of the new mixture? Correct Answer 1/6

Quantity of cement in 60 kg mixture = 30% of 60 = 18 kg

Let ‘x’ kg of cement be added to obtain the new mixture

Quantity of cement in new mixture = 18 + x

Quantity of new mixture = 60 + x

∵ Cement in new mixture is 5/12 part of the mixture

⇒ 18 + x = 5/12(60 + x)

⇒ 216 + 12x = 300 + 5x

⇒ 12x – 5x = 300 – 216

⇒ x = 84/12 = 12 kg

Now,

Quantity of new mixture = 60 + 12 = 72 kg

Quantity of sand in new mixture = Quantity of sand in old mixture = 20% of 60 = 12 kg

∴ The sand in new mixture is 12/72 = 1/6 part of the new mixture

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