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Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answer. Quantity A: What will be the compound interest on Rs. 16000 for 9 months at 20% p.a. compounded quarterly. Quantity B: A man borrows Rs. 4000 at 20% compound rate of interest. At the end of each year he pays back Rs. 1500. What amount should he pay at the end of the third year to clear all his dues?

Given below are two quantities named A and B. Based on the given information, you have to determine the relation between the two quantities. You should use the given data and your knowledge of Mathematics to choose between the possible answer. Quantity A: What will be the compound interest on Rs. 16000 for 9 months at 20% p.a. compounded quarterly. Quantity B: A man borrows Rs. 4000 at 20% compound rate of interest. At the end of each year he pays back Rs. 1500. What amount should he pay at the end of the third year to clear all his dues? Correct Answer Quantity A < Quantity B

Quantity A:

P = 16000, r(quarterly) = 20/4 = 5%, n = 3 (9 months)

CI =

CI = 18522 – 16000 = Rs 2522

Quantity B:

For 1st year:

Interest = (4000 × 20 × 1)/100 = Rs. 800

Amount = Rs. 4800

∵ He is paying Rs. 1500 at the end of each year;

∴ Principle for 2nd year = 4800 – 1500 = 3300

For 2nd year:

Interest = (3300 × 20 × 1)/100 = Rs. 660

Amount = 3300 + 660 = 3960

∵ He is paying Rs. 1500 at the end of each year;

∴ Principle for 3rd year = 3960 – 1500 = 2460

For 3rd year:

Interest = (2460 × 20 × 1)/100 = Rs. 492

Amount = 2460 + 492 = Rs. 2952

∴[ alt="clip image002" src="file:///C:/Users/UMESHK~1/AppData/Local/Temp/msohtmlclip1/01/clip_image002.gif">He will pay Rs. 2952 at the end of 3rd year to clear his dues.

∴ Quantity A < Quantity B

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