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There are 15 balls of three colors Red, Blue and Green in a box. The number of balls of all three colors is different. The difference of Red and Blue color balls is equal to the difference of Blue and Green color balls. If a ball is drawn at random from the box then the probability of getting a Green ball is always more than 0.2. What can be the possible number of Green balls in the box? A. 4 B. 7 C. 5 D. 8 E. 3

There are 15 balls of three colors Red, Blue and Green in a box. The number of balls of all three colors is different. The difference of Red and Blue color balls is equal to the difference of Blue and Green color balls. If a ball is drawn at random from the box then the probability of getting a Green ball is always more than 0.2. What can be the possible number of Green balls in the box? A. 4 B. 7 C. 5 D. 8 E. 3 Correct Answer A, B and D

The difference of Red and Blue colour balls is equal to the number of Blue and Green colour balls;

∴ R – B = B – G or

B – R = G – B

In both cases:

2B = R + G      ---- (1)

Given that: R + B + G = 15

From equation 1:

⇒ 3B = 15

⇒ B = 5

Hence, R + G = 10

Possible values of G are: 1, 2, 3, 4, 6, 7, 8, 9

It is given that the probability of getting a Green ball is always more than 0.2;

∴ G/15 > 1/5

Or

G/15 > 3/15

∴ G > 3

Hence possible values of G: 4, 6, 7, 8, 9

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