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Angle of elevation of to the top of a tower from top and bottom of a building are 30° and 45° respectively. If a man standing at bottom of the building walk 7.32 meter towards tower angle of elevation become 60° what is the height of the building?

Angle of elevation of to the top of a tower from top and bottom of a building are 30° and 45° respectively. If a man standing at bottom of the building walk 7.32 meter towards tower angle of elevation become 60° what is the height of the building? Correct Answer 7.32 meter

⇒ BD = √3 × AF    ----(1)

In ΔABD

tan 45° = AB/BD

⇒ BD = AB

In ΔABE

tan 60° = AB/BE

⇒ √3 = AB/BE

⇒ √3 × BE = BD    ----(2)

From equation (1) and equation (2)

⇒ √3 × BE = √3 × AF

⇒ BE = AF

Now, BD = AB

⇒ BE + ED = AF + FB   

⇒ AF + ED = AF + FB                 

⇒ ED = FB

∵ FB = CD

CD = 7.32 meter

∴ the height of the building is 7.32 meter

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