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A box contains 2 blue caps, 4 red caps, 5 green caps and 1 yellow cap. If one cap is picked at random, what is the probability that it is either blue or yellow?

A box contains 2 blue caps, 4 red caps, 5 green caps and 1 yellow cap. If one cap is picked at random, what is the probability that it is either blue or yellow? Correct Answer 1/4

Total number of caps in box = (2 blue + 4 red + 5 green + 1 yellow) caps = 12

Let,

E1 = event of picking a blue cap

E2 = event of picking a yellow cap

Then,

P(E1 ) = 2/12

P(E2) = 1/12

∴ probability of picking a cap that it is either blue or yellow = 2/12 + 1/12 = 3/12 = ¼

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