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Consider the following particulars in respect of a concrete mix design:   Weight Specific Gravity Cement 400 kg/m3 3.2 Find aggregates - 2.5 Coarse aggregates 1040 kg/m3 2.6 Water 200 kg/m3 1.0   What shall be the weight of the Fine aggregates?

Consider the following particulars in respect of a concrete mix design:   Weight Specific Gravity Cement 400 kg/m3 3.2 Find aggregates - 2.5 Coarse aggregates 1040 kg/m3 2.6 Water 200 kg/m3 1.0   What shall be the weight of the Fine aggregates? Correct Answer 690 kg/m<sup>3</sup>

Concept

Volume of concrete = Volume of F.A + Volume of C.A + Volume of Cement + Volume of Water + Volume of air

Where,

F.A is fine aggregate

CA is coarse aggregate

Calculation

Let volume of Concrete is 1 m3 and assume that there is not air content.

Composition

Weight per

1 m3  Concrete

Actual weight

Specific Gravity

Density = specific  gravity × 1000

Volume = mass/density

Cement

400 kg/m3

400 kg

3.2

3200 kg/m3

0.125 m3

Find aggregates(FA)

-

‘x’ kg

2.5

2500 kg/m3

x/2500 m3

Coarse aggregates(CA)

1040 kg/m3

1040 kg

2.6

2600 kg/m3

0.4 m3

Water

200 kg/m3

200 kg

1.0

1000 kg/m3

0.2 m3

Air

NIL (assumed as it is  not given)

 

Now,

V = VFA + VCA + Vcement + Vwater + Vair

1 = x/2500 + 0.4 + 0.125 + 0.2 + 0

∴ Weight of Fine aggregates, x = 687.5 Kg  ≈ 690 kg

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