12x + 6y = 3 . . . . . . . . (i) 5x + 3y = 11 . . . . . . . . (ii) Multiplying equation (ii) by 2 and subtracting it from equation (i) we get 12x+ 6y = 3 10x + 6y = 22 12x - 10x = -19 ⇒ 1-202x = -19 ⇒ -192x = -19 ⇒ 12x = 1 [Dividing both sides by - 19] ⇒ 2x = 1 ∴ x = 12 Putting the value of x in equation (i), we get 12x + 6y = 3 ⇒ 12 × 12+ 6y = 3 ⇒ 1 + 6y= 3 ⇒6y = 3-1 = 2 ⇒6y = 2 ⇒3y = 1 [Dividing both sides by 2] ∴ y = 3 ∴ x,y= 12, 3 (Answer)
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