In a certain class, of the boys are shorter than the shortest girls in the class and of the are taller than the tallest boy in the class. If there are 16 students in the class and no t people have the same height, what percent of the students are taller than the shortest girl shorter than the tallest boy?

Given, total students = 16 

As, the number of boys is the multiple of 5

So, the possible number of boys may be 5, 10, 15 

And the number of girls is the multiple of 3

So, the possible number of girls may be 3, 6, 9, 12, 15 

According to the question,

The number of boys may be = 10 and the number of girls may be = 6 

The number of boys taller than the shortest girl = $10\times \frac{1}{5} = 2$

And the number of girls shorter than the tallest boy =$6\times \frac{1}{3} = 2$

Here, there is 1 shortest boy and 1 tallest girl. The number of students taller than the shortest girl and the shorter than the tallest boy =16-(2+2+1+1) = 10

Required percentage = $\left(\frac{10}{16}\times 100\right)\%=62.5$