শর্তমতে, x2 + y2 = 13 এবং xy = 6
(x - y)2 = x2 + y2 - 2xy = 13 – (2 × 6) = 13 – 12 = 1
∴ x - y = 1
∴ x+y = x-y2 + 4 ×xy = 12+ 4×6 = 1+24 = 25=5
∴ x2 - y2 = (x + y) (x - y)
⇒ x2 - y2 = 5 ×1 = 5
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