ধরি, ∫a = a3 - 6a2 + 12a-9
এখানে, a = 3 ধরলে ∫(a) = 0 হয়।
তাই (a – 3) হবে ∫a এর একটি উৎপাদক।
এখন, a3-6a2 + 12a-9
= a3-3a2-3a2+9a+3a-9 = a2 (a-3)-3a (a-3)+3 (a-3) = (a-3)(a2-3a + 3)
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