The amount of oxalic acid (eq. wt 63) required to preare 500 ml of its 0.10 N solution is
A. `0.315g`
B. `3.150g`
C. `6.300g`
D. `63.00g`

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1 Answers

Correct Answer - B
`w = (N xx GEW xx V("in ml"))/(1000)`

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