A system is provided with 50 Joules of heat and the work done on they system is 10 Joules. What is the change in internal energy of the system in Joul

Given: q0 = 4 C, VA = -10 volt, VB = V volt, WAB = 100 J To Find: Potential (V) Formula: VB – VA = \(\frac{W_{AB}}{q_0}\) Calculation: From formula, V – (-10) = \(\frac{100}{4}\) = 25 ∴ V + 10 = 25 ∴ V = 15...

Correct option is A) gain

Correct option is B) lose

Correct option is A) transferred

C) latent heat

(b) physical change

Correct Answer - B Kilowatt hour is the commerical unit of electrical energy. It is donated by kW h.

Correct Answer - 20

Correct Answer - B `C=(R)/(gamma-1)+p(dV)/(dT)` `=(R)/(gamma-1)+alphaV.(R)/(2alphaV)=(R)/(gamma-1)+(R)/(2)=(R(gamma+1))/(2(gamma-1))` `Q=-DeltaU=DeltaU+W , or W=-2DeltaU` `C=(R)/(gamma-1)+((-2RdT)/((gamma-1)dT))=(R)/(1-gamma)` `pdV=(-2RdT)/(gamma-1)` `(RT)/(V)dV=(-2)/(gamma-1)RdT(dT)/(T)=-((gamma-1))/(2)(dV)/(V)` log `T=-((gamma-1))/(2)logV =logV^(-(gamma-1)/(2))+logK` or log `TV^((gamma-1)/(2))=` constant