Radiatonal wavelength `(lambda)=124nm` falls on a metallic surface then the kinetic energy of the ejected photo electron(s) can be : [Given that thres

Question

Radiatonal wavelength `(lambda)=124nm` falls on a metallic surface then the kinetic energy of the ejected photo electron(s) can be : [Given that thres

Radiatonal wavelength `(lambda)=124nm` falls on a metallic surface then the kinetic energy of the ejected photo electron(s) can be : [Given that threshold wavelength `(lambda_(0))=248nm]`
A. 1 eV
B. 2 eV
C. 3 eV
D. 5 eV

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - a b c d

4 views Answered 2023-02-05 15:29