Equation of the hyperbola with eccentricty 3/2 and foci at (± 2, 0) is

Equation of the hyperbola with eccentricty 3/2 and foci at (± 2, 0) is

(A) x²/4 -y²/5 = 4/9

(B) x²/9 - y²/9 = 1

(C) x²/4 - y²/9 = 1

(D) none of these

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Answer is (A)

7 views Answered 2023-02-05 15:29

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