A simple pendulum of mass m and length l stands in equilibrium in vertical position. The maximum horizontal velocity that should be given to the bob at the bottom so that it completes one revolution is

(A)  \(\sqrt{lg}\)

(B)  \(\sqrt{2lg}\)

(C)  \(\sqrt{3lg}\)

(D)  \(\sqrt{5lg}\)

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Answer is  (D)  \(\sqrt{5lg}\)

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