If ΔABC is right angled at C, then the value of cos (A+B) is (A) 0 (B) 1 (C) 1 2 (D) √3/2
If ΔABC is right angled at C, then the value of cos (A+B) is
(A) 0 (B) 1 (C) 1 2 (D) √3/2
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