If sin 3A = cos (A – 26°), where 3A is an acute angle, find the value of A.
If sin 3A = cos (A – 26°), where 3A is an acute angle, find the value of A.
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sin 3A = cos (A - 26°)
cos(90° - 3A) = cos (A -26°)
90° - 3A = A - 26°
4A = 116°
A = \(\frac{116°}{4} = 29°\)
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