let length of the rectangle be L and breadth be B
so by the problem perimeter 2(IL+B)=34
=> L+B =17 .......(1)
=> L2+B2+2LB=289 ..........(2)
and the square of the diagonal = L2+B2=132 =169 .....(.3)
By...
Correct option is (D) Q3
\(\because\) \((x_1,y_1)\) lies in \(Q_2\)
\(\therefore\) \(x_1<0\) & \(y_1>0\)
Also given that \((x_2,y_2)\) lies in \(Q_3.\)
\(\therefore\) \(x_2<0\), \(y_2<0\)
\(\because\) \(x_1<0\) & \(y_2<0\)
\(\therefore\) \((x_1,y_2)\) lies in \(Q_3\)
