i. Three resistors 1 Ω, 2 Ω and 3 Ω are combined in series. What is the total resistance of the combination?
i. Three resistors 1 Ω, 2 Ω and 3 Ω are combined in series. What is the total resistance of the combination?
ii. If the combination is connected to a battery of e.m.f. 12 V and negligible internal resistance, obtain the potential drop across each resistor.
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Given: R1 = 1Ω, R2 = 2 Ω, R3 = 3 Ω,
V = 12 V
To Find: i. Total resistance (R)
ii. P.D Across R1, R2, R3 (V1, V2, V3 respectively)
Formulae:
i. Rs = R1 + R2 + R3
ii. V = IR
Calculation:
From formula (i):
Rs = l + 2 + 3 = 6 Ω
From formula (ii),
1 = \(\frac{V}{R}=\frac{12}{6}\) = 2A
∴ V1 = IR1 = 2 × 1 = 2 V
∴ V2 = IR2 = 2 × 2 = 4 V
∴ V3 = IR3 = 2 × 3 = 6 V
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