The value of p if px^4 + 7x^2 – 18 is divisible by (x – 3)
The value of p if px4 + 7x2 – 18 is divisible by (x – 3)
A) 9/5
B) -5/9
C) 5/9
D) 1
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Correct option is (B) -5/9
\(\because\) \(px^4+7x^2-18\) is divisible by (x - 3).
\(\therefore\) When \((px^4-7x^2-18)\) is divided by (x - 3), it leaves remainder 0.
\(\therefore\) \(p(3)^4+7\times3^2-18=0\)
\(\Rightarrow\) 81p + 63 - 18 = 0
\(\Rightarrow\) 81p = -63 + 18
\(\Rightarrow\) 81p = -45
\(\Rightarrow\) \(p=\frac{-45}{81}=\frac{-5}{9}\)
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