The remainder when 2x^3 + 3x^2 +4x + 5 is divided by (x – 2)
The remainder when 2x3 + 3x2 +4x + 5 is divided by (x – 2)
A) 31
B) 29
C) 36
D) 41
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Correct option is (D) 41
Let p(x) = \(2x^3+3x^2+4x+5\)
When p(x) is divided by \((x-2)\) then remainder will be p(2).
\(\therefore\) Remainder = p(2) \(=2\times2^3+3\times2^2+4\times2+5\)
= 16+12+8+5 = 41
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