For the collision,
u1 = 400 m s-1, e = 0.75
For the firmly fixed hard surface, u2 = v2 = 0
e = 0.75 = \(\frac{v_1-v_2}{u_2-u_1}=\frac{v_1-0}{0-400}\)
∴ v1 = -300 m/s.
Negative sign indicates that the bullet rebounds in exactly...
Given: m = 0.1 kg, u = 20 m/s, t = 0.1 s
To find: Impulse (J), Average force (F)
Formulae:
i. J = mv – mu
ii. F = \(m\frac{(v-u)}{t}\)
Calculation:
From formula (i).
J = m(v...