A ray of light passes from glass (ng = 1.52) to water (nw = 1.33). What is the critical angle of incidence?
A ray of light passes from glass (ng = 1.52) to water (nw = 1.33). What is the critical angle of incidence?
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Given: ng = 1.52, nw = 1.33
To find: Critical angle (ic)
formula: sin ic = \(\frac{n_2}{n_1}=\frac{n_w}{n_g}\)
Calculation:
From formula,
ic = sin-1 \((\frac{1.33}{1.52})\) = sin-1 (0.875) = 61 °2′
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