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If -3 is a root of the quadratic equation X²+mx-3=0 and x²+mx+n =0 has equal roots then the value of n is

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Let the equations be F(x) and F'(x)

For F , let say roots are -3 and a.

a-3 = -m, -3a = -3, a = 1

So roots of F are 1 and -3

And m = 3-a = 2

F' is x^2 +2x+n = 0

D = 0

Or 4–4n = 0

n = 1

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