Escape velocity on a planet is ve. If radius of the planet remains same and mass becomes 4 times, the escape velocity becomes

Escape velocity on a planet is ve. If radius of the planet remains same and mass becomes 4 times, the escape velocity becomes

(A) 4v_e

(B) 2ve

(C) v_e

(D) 0.5 v_e

Monjur Alahi

5 views

2025-01-04 04:42

2 Answers

Salim Ahmed Kawsar

Correct option is: (B) \(2v_e\)

Escape Velocity

\(v_e = \sqrt {2gRe}\)

\(\frac{V_{e1}}{V_{e2}} \propto \sqrt \frac{4R_1}{R_1}\)

\(V_{escape \ 2} = 2 \ V_{escape \ 1}\)

5 views Answered 2023-02-05 15:29

Salim Ahmed Kawsar

Correct option is: (B) 2v_e

5 views Answered 2023-02-05 15:29

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